Given: A circle with center ‘O’. Having points P and Q subtends angles ∠PAQ and ∠PBQ at points A and B.
To Prove: ∠PAQ = ∠PBQ
Proof: From Theorem 10.8: Angle subtended by an arc at the center is double the angle subtended by it at any other point on the circle.
Therefore, ∠POQ = 2∠PAQ ….(i)
and, ∠POQ = 2∠PBQ ….(ii)
from eq(i) and (ii), we get
2∠PBQ = 2∠PAQ
∠PBQ = ∠PAQ
Hence,Proved.